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0=-3x^2+2.7x+3.8
We move all terms to the left:
0-(-3x^2+2.7x+3.8)=0
We add all the numbers together, and all the variables
-(-3x^2+2.7x+3.8)=0
We get rid of parentheses
3x^2-2.7x-3.8=0
a = 3; b = -2.7; c = -3.8;
Δ = b2-4ac
Δ = -2.72-4·3·(-3.8)
Δ = 52.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.7)-\sqrt{52.89}}{2*3}=\frac{2.7-\sqrt{52.89}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.7)+\sqrt{52.89}}{2*3}=\frac{2.7+\sqrt{52.89}}{6} $
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